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4+31x-8x^2=0
a = -8; b = 31; c = +4;
Δ = b2-4ac
Δ = 312-4·(-8)·4
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-33}{2*-8}=\frac{-64}{-16} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+33}{2*-8}=\frac{2}{-16} =-1/8 $
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